Answer:
Let, No. of tickets sold at Rs. 20 be ‘ x’
No. of tickets sold at Rs. 40 be ‘ y’
According to the first condition,
x + y = 35 ——————————–A
According to the second condition,
20x + 40y = 900
Dividing above equation by 20 on both sides
x + 2y = 45 —————-B
Solving equation A and B by elimination method,
x + y = 35
x + 2y = 45
0x -y = – 10
hence, y = 10
Put y =10 in equation A,
x + y = 35
x + 10 =35
x = 35-10
x = 25
Answer:
No of tickets sold for Rs. 20 = 25, and
No. of tickets sold for Rs. 40 = 10